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The foot of a ladder is 6 m away from a wall and its top reaches a window 8 m above the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its tip reach?

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Let length of ladder be AD = BE = 1m 

In ΔACD 

AD2 = AC2 + CD2 

t= 82 + 62 ………………..(i) 

In ΔBCE 

BE2 = BC2 + EC2 

t2 = BC+ 82 …………….. (II) 

From (i) and (ii) 

BC2 + 82 = 82 + 62 

BC2 = 62 

BC = 6m

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