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in Parallelograms by (26.9k points)
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In a parallelogram ABCD, if ∠DAB = 75° and ∠DBC = 60°, then ∠BDC = 

A. 75° 

B. 60° 

C. 45° 

D. 55°

1 Answer

+1 vote
by (27.3k points)
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Best answer

Option : (C)

We know that, 

The opposite angles of a parallelogram are equal 

Therefore, 

∠BCD = ∠BAD = 75° 

Now, 

In BCD, we have 

∠CDB + ∠DBC + ∠BCD = 180°

(Since, sum of the angles of a triangle is 180°) 

∠CDB + 60° + 75° = 180° 

∠CDB + 135° = 180° 

∠CDB = (180° - 135°) 

= 45°

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