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in Parallelograms by (26.9k points)
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The diagonals of a parallelogram ABCD intersect ay O. If ∠BOC = 90° and ∠BDC = 50°, then ∠OAB = 

A. 40° 

B. 50° 

C. 10° 

D. 90°

1 Answer

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Best answer

Option : (A)

∠BOC is 90° 

So, 

∠COD and ∠AOB all should be 90° by linear pair 

∠BDC is 50°, 

So, 

Now as in a parallelogram the opposite sides are equal 

We say, 

AB parallel to CD 

∠DCA = 50° 

So, 

In triangle COA 

∠C = 50° (Stated above) 

∠COA = 90° (Proved above) 

Therefore, 

90° + 50° + x° = 180° 

x = 40°

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