\(\frac{3}{x+y}\)+\(\frac{2}{x-y}\)= 2
\(\frac{9}{x+y}\) - \(\frac{4}{x-y}\) = 1
Multiplying eq1 by 2 and adding to eq2
⇒ 15/(x + y) = 5
⇒ x + y = 3 ------- (3)
Multiplying eq1 by 3 and subtracting eq2 from it
⇒ 10/(x – y) = 5
⇒ x – y = 2 ---- (4)
Adding the two equation
⇒ 2x = 5
⇒ x = 5/2
Thus,
y = 1/2