​ Solve the following systems of equations: 4/x + 3y = 14 3/x + 4y = 23 ​

Question

Solve the following systems of equations:

\(\frac{4}{x}\)+ 3y = 14

\(\frac{3}{x}\)+ 4y = 23

Answer 1

 \(\frac{4}{x}\)+ 3y = 14

\(\frac{3}{x}\)+ 4y = 23

Multiply eq1 by 4 and eq2 by 3 and adding

⇒ 25/x = 125

⇒ x = 1/5

Thus,

20 + 3y = 14

⇒ y = - 2