\(\frac{44}{x+y}\)+\(\frac{30}{x-y}\) = 10
\(\frac{55}{x-y}\)+\(\frac{40}{x-y}\) = 13
Multiplying eq1 by 5 and eq2 by 4 and subtracting
⇒ - 10/(x – y) = - 2
⇒ x – y = 5
Multiply eq1 by 4 and eq2 by 3 and subtracting
⇒ 11/(x + y) = 1
⇒ (x + y) = 11
Thus,
2x = 16
⇒ x = 8
∴ y = 8 – 5 = 3