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A heap of wheat is in the form of a cone of diameter 9 m and height 3.5 m. Find its volume. How much canvas cloth is required to just cover the heap? (Use π =3.14)

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We have,

radius = 9/2 = 4.5 m 

height = 3.5 m 

∴ slant height l = \(\sqrt{r^2+h^2}\) 

\(\sqrt{(4.5)^2+(3.5)^2}\)

= 5.70 m

∴ Volume of the heap = \(\frac{1}{3}\)πr2h

= \(\frac{1}{3}\)×3.14×(4.5)2×3.5 

= 74.1825 m3

Area of canvas required = πrl 

= 3.14×4.5×5.7 m2 

= 80.54 m2

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