Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
473 views
in Linear Equations by (49.4k points)
closed by

Solve each of the following systems of equations by the method of cross-multiplication:

(a - b)x + (a + b)y = 2a2 - 2b2

(a + b)(x + y) = 4ab

1 Answer

+1 vote
by (50.9k points)
selected by
 
Best answer

Method of cross multiplication:For the system of equations:

a1x + b1y + c1 = 0

a2x + b2y + c2 = 0

Here,

a1 = (a - b),

b1 = (a+b) ,

c1 = 2b2 - 2a2a2 = (a+b),

b2 = (a+b),

c2 = - 4a

So,

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...