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+1 vote
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in Linear Equations by (49.4k points)
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The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, he buys 3 bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.

1 Answer

+1 vote
by (50.9k points)
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Best answer

Let the cost of each bat be ‘a’ and each ball be ‘b’.

Given, coach of a cricket team buys 7 bats and 6 balls for Rs 3800.

Later,

He buys 3 bats and 5 balls for Rs 1750

⇒ 7a + 6b = 3800 ---- (1)

and 3a + 5b = 1750 ---- (2)

Multiplying eq1 by 3 and eq2 by 7 and subtracting eq2 from eq1.

⇒ 3(7a + 6b) - 7(3a + 5b) = 3(3800) - 7(1750)

⇒ 21a + 18b – 21a – 35b = 11400 – 12250 

⇒ -17b = - 850

⇒ 17b = 850

⇒ b = 50

Putting this in eq 1, we get

7a + 6(50) = 3800

⇒ 7a + 300 = 3800

⇒ 7a = 3500

⇒ a = 500

Hence,

Each bat cost a = 500 Rupees and Each ball costs b = 50 Rupees.

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