Let the present age of man be ‘a’ and present age of son be b.

**Given,**

Six years hence a man’s age will be three times the age of his son and three years ago he was nine times as old as his son

⇒ a + 6 = 3(b + 6)

⇒ a = 3b + 12 ------ (1)

**Also,**

Three years ago he was nine times as old as his son

⇒ a – 3 = 9(b – 3)

⇒ a = 9b – 24 ----- (2)

**Equating eq1 and eq2**

⇒ 3b + 12 = 9b – 24

⇒ b = 6

**Thus,**

a = 3b + 12 = 30

**Hence age of man is 30 yrs and age of son is 6 yrs.**