Let the present age of man be ‘a’ and present age of son be b.
Given,
Six years hence a man’s age will be three times the age of his son and three years ago he was nine times as old as his son
⇒ a + 6 = 3(b + 6)
⇒ a = 3b + 12 ------ (1)
Also,
Three years ago he was nine times as old as his son
⇒ a – 3 = 9(b – 3)
⇒ a = 9b – 24 ----- (2)
Equating eq1 and eq2
⇒ 3b + 12 = 9b – 24
⇒ b = 6
Thus,
a = 3b + 12 = 30
Hence age of man is 30 yrs and age of son is 6 yrs.
