Option : (A)
Volume of a sphere = \(\frac{4}{3}\)πr3
Volume of a solid cone = \(\frac{1}{3}\)πr2h
Given,
solid sphere of radius r is melted and cast into the shape of a solid cone of height r
Let the base radius be A.
⇒ \(\frac{4}{3}\)πr3 = \(\frac{1}{3}\)π × A2 × r
⇒ A = 2r