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in Arithmetic Progression by (49.2k points)
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The 6th and 17th terms of an A.P. are 19 and 41 respectively, find the 40th term.

1 Answer

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Best answer

a6 = 19 = a + (n – 1) d

= 19 = a + 5d …(i)

A17 = 41 = a + (n – 1) d

= 41 = a + 16d …(ii)

Subtracting (i) from (ii), we get

22 = 11d

d = 2

Now substituting the value of d in (i):

19 = a + 10

= a = 9

A40 = a + (40 – 1) 2

= 9 + 78

= 87

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