Sarthaks Test
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ΔABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height AD from A to BC, is 6 cm. Find the area of Δ ABC. What will be the height from C to AB i.e., CE?

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 In Δ ABC, AD = 6 cm and BC = 9 cm 

Area of triangle = 1/2 x base x height 

= 1/2 x BC x AD 

= 1/2  x 9 x 6 = 27 cm2  

Again, Area of triangle = 1/2 x base x height 

=1/2 x AB x CE 

⇒ 27 = 1/2 x 7.5 x CE 

⇒ CE = (27 x 2) / 7.5 

⇒ CE = 7.2 cm 

Thus, height from C to AB i.e., CE is 7.2 cm.

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