Sarthaks Test
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In a right triangle ABC, ∴ B = 90°.

(a) If AB = 6 cm, BC = 8 cm, find AC

(b) If AC = 13 cm, BC = 5 cm, find AB

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(a) ΔABC is right-angled at B.

Therefore, by applying Pythagoras theorem, we obtain

AC2 = AB2 + BC2

AC2 = (6 cm)2 + (8 cm)2

AC2 = (36 + 64) cm2 =100 cm2

AC = (√100) cm = (√10x10) cm

AC = 10 cm

(b) ΔABC is right-angled at B.

Therefore, by applying Pythagoras theorem, we obtain

AC2 = AB2 + BC2

(13 cm)2 = (AB)2 + (5 cm)2

AB2 = (13 cm)2 − (5 cm)2 = (169 − 25) cm2 = 144 cm2

AB = (√144) cm = (12x12) cm

AB = 12 cm

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