(a) ΔABC is right-angled at B.
Therefore, by applying Pythagoras theorem, we obtain
AC2 = AB2 + BC2
AC2 = (6 cm)2 + (8 cm)2
AC2 = (36 + 64) cm2 =100 cm2
AC = (√100) cm = (√10x10) cm
AC = 10 cm
(b) ΔABC is right-angled at B.
Therefore, by applying Pythagoras theorem, we obtain
AC2 = AB2 + BC2
(13 cm)2 = (AB)2 + (5 cm)2
AB2 = (13 cm)2 − (5 cm)2 = (169 − 25) cm2 = 144 cm2
AB = (√144) cm = (√12x12) cm
AB = 12 cm