To find: Speed of the train
Method 1: Let the speed of the train be x km/hr.
Time taken to cover 360 km \(=\frac{360}{x}\) hr,
As
Now, given that if the speed would be 5 km/hr more, the same distance would be covered in 1 hour less, i.e.if speed = x + 5, and
then, using distance = speed x time, we have
Now we can form the quadratic equation from this equation
Now, cross multiplying we get
360 x - x2 + 1800 - 5 x = 360 x
x2 + 5 x – 1800 = 0
Now we have to factorize in such a way that the product of the two numbers is 1800 and the difference is 5x2 + 45 x – 40 x – 1800 = 0
x(x + 45) – 40(x + 45) = 0
(x + 45)(x – 40 ) = 0
x = - 45, 40
since, the speed of train can’t be negative,so, speed will be 40 km/hour.