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in Quadratic Equations by (31.2k points)
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The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer side is 30 metres more than the shorter side, find the sides of the field

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Let the shorter side be ‘a’. 

Given, diagonal of a rectangular field is 60 metres more than the shorter side 

Diagonal = a + 60 

Also, longer side is 30 metres more than the shorter side 

Longer side = a + 30 

Hypotenuse2 = length2 + breadth

⇒ (a + 60)2 = (a + 30)2 + a

⇒ a2 + 120a + 3600 = a2 + 60a + 900 + a2 

⇒ a2 – 60a – 2700 = 0 

⇒ a2 – 90a + 30a – 2700 = 0 

⇒ a(a – 90) + 30(a – 90) = 0 

⇒ (a + 30)(a – 90) = 0 

⇒ a = 90m 

Length of sides = 90m, 120 m

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