Question

If the equation x² – bx + 1 = 0 does not possess real roots, then

A. – 3 < b < 3 

B. – 2 < b < 2 

C. b > 2 

D. b < – 2

Answer 1

If the equation does not possess real roots then 

d = b² – 4ac = 0 

Here a = 1, b = – b, c = 1 

d = b² – 4 < 0 

b² < 4 

b < \(\pm\) 2 

– 2 < b < 2