In a △ABC, right angled at B, AB = 24 cm, BC = 7 cm. Therefore, By Pythagoras Theorem,
AC2 = AB2 + BC2
AC2 = 242 + 72
AC2 = 576 + 49
AC2 = 625
AC = 25
Therefore
SinA = \(\frac{BC}{AC}\) = \(\frac{7}{25}\),
CosA = \(\frac{AB}{AC}\) = \(\frac{24}{25}\)
SinC = \(\frac{AB}{AC}\) = \(\frac{24}{25}\)
CosC = \(\frac{BC}{AC}\) = \(\frac{7}{25}\)