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From an external point P, tangents PA are drawn to a circle with centre O. If CD is the tangent to the circle at a point E and PA = 14 cm, find the perimeter of \(\Delta PCD.\)

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Given: PA and PB are tangent to the circle with centre O

CD is tangent to the circle at E which intersect PA and PB in C and D

To find : Perimeter of triangle PCD

Proof:

PA = PB

CA = DE

DB = DE

PA = PB = 14cm

Perimeter of ΔPCD = PC + CD + PD

= PA + PB = 14 + 14 = 28cm

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