Given: PA and PB are tangent to the circle with centre O
CD is tangent to the circle at E which intersect PA and PB in C and D
To find : Perimeter of triangle PCD
Proof:
PA = PB
CA = DE
DB = DE
PA = PB = 14cm
Perimeter of ΔPCD = PC + CD + PD
= PA + PB = 14 + 14 = 28cm