Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
170 views
in Arithmetic Progression by (49.2k points)
closed by

The 10th and 18th terms of an A.P. are 41 and 73 respectively. Find 26th term.

1 Answer

+1 vote
by (50.7k points)
selected by
 
Best answer

a10 = 41

a + (10 – 1)d = 41

a + 9d = 41 …(i)

a18 = 73

a + (18 – 1)d = 73

Substituting the value of a from (i),

41 – 9d + 17d = 73

8d = 32

d = 4

a = 41 – 9(4)

a = 41 – 36

a = 5

a26 = a + (26 – 1)d

= 5 + 25(4)

= 5 + 100

= 105

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...