Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
454 views
in Definite Integrals by (29.3k points)
closed by

Find the area of the region common to the circle x2 + y2 = 16 and the parabola y2 = 6x.

1 Answer

+1 vote
by (28.8k points)
selected by
 
Best answer

There are two equations,

And when x = 2 then y = ±2√3

Equation (i) represents a circle with centre (0, 0) and radius 4 units, so it meets x - axis at (±4, 0) and equation (ii) represents a parabola with vertex (0,) and axis as x - axis

Points of intersection of parabola and circle are (2, 2√3) and (2, – 2√3).

The sketch of the two curves are drawn below,

The shaded region represents the required area.

Required area = Region OBCAO

Required area = 2 (region ODAO + region DCAD)

So, the required area is 2\(\big\{\frac{2\sqrt{3}}{3} + \frac{8\pi}{3}\big\}\) sq units.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...