There are two equations,
And when x = 2 then y = ±2√3
Equation (i) represents a circle with centre (0, 0) and radius 4 units, so it meets x - axis at (±4, 0) and equation (ii) represents a parabola with vertex (0,) and axis as x - axis
Points of intersection of parabola and circle are (2, 2√3) and (2, – 2√3).
The sketch of the two curves are drawn below,
The shaded region represents the required area.
Required area = Region OBCAO
Required area = 2 (region ODAO + region DCAD)
So, the required area is 2\(\big\{\frac{2\sqrt{3}}{3} + \frac{8\pi}{3}\big\}\) sq units.