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in Arithmetic Progression by (49.4k points)
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The 7th term of an A.P. is 32 and its 13th term is 62. Find the A.P.

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Best answer

a7 = 32

a + 6d = 32 (i)

a13 = a + 12d = 62 (ii)

By subtracting (i) from (ii), we get

6d = 30

d = 5

From (i), a = 32 – 6(5) = 2

We have to find A.P.

a1 = 2

a2 = a + d = 2 + 5 = 7

a3 = a + 2d = 2 + 2(5) = 12

a4 = a + 3d = 2 + 3(5) = 17

Hence, A.P. is 2, 7, 12, 17,…

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