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in Arithmetic Progression by (49.2k points)
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Find the 10th term from the end of the A.P. 8, 10, 12, ..., 126

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Best answer

Given, First term, a = 8

Common difference, d = 2

Let the number of terms be 'n'

We know, nth term of an AP is an = a + (n – 1)d where ‘a’ and ‘d’ are first term and common difference of AP respectively

Last term, an = 126

⇒ an = a + (n – 1) d

⇒ 126 = 8 + (n – 1) 2

⇒ 120 = 2n

⇒ n = 60

Now we have to find last 10th term, means = 60th term – 10 + 1 = 51th term

Now, a51 = 8 + (51 – 1)2

= 8 + 50(2) = 8 + 100= 108

Hence, 10th term from the last of given A.P. is 108

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