Given, First term, a = 8
Common difference, d = 2
Let the number of terms be 'n'
We know, nth term of an AP is an = a + (n – 1)d where ‘a’ and ‘d’ are first term and common difference of AP respectively
Last term, an = 126
⇒ an = a + (n – 1) d
⇒ 126 = 8 + (n – 1) 2
⇒ 120 = 2n
⇒ n = 60
Now we have to find last 10th term, means = 60th term – 10 + 1 = 51th term
Now, a51 = 8 + (51 – 1)2
= 8 + 50(2) = 8 + 100= 108
Hence, 10th term from the last of given A.P. is 108