**Given:**

PB = 10 cm

CQ = 2 cm

**Property: **If two tangents are drawn to a circle from one external point, then their tangent segments (lines joining the external point and the points of tangency on circle) are equal.

Using the above property,

PA = PB = 10 cm (tangent from P)

DB = DQ= 10 cm (tangent from D)

**And, **

CA = CQ= 10 cm (tangent from C)

**Now,**

Perimeter of ∆PCD = PC + CD + DP

= PC + CQ + QD + DP

= PC + CA + DB + PD [∵CA = CQ and DB = DQ]

= PA + PB [∵PA = PC + CA and PB = PD + BD]

= 10 cm + 10 cm

= 20 cm

**Hence, Perimeter of ∆PCD = 20 cm**