Let I = \(\int\limits_0^1\cfrac{1-\text x^2}{\text x^4+\text x^2+1}d\text x \)
In the denominator, we have x4 + x2 + 1
Note that we can write x4 + x2 + 1 = (x4 + 2x2 + 1) – x2
We have x4 + 2x2 + 1 = (1 + x2)2
⇒ x4 + x2 + 1 = (1 + x2)2 – x2
So, using this, we can write our integral as
Dividing numerator and denominator with x2, we have
(Differentiating both sides)
So, the new limits are ∞ and 2.
Substituting this in the original integral,