**Given:**

CP = 11 cm

BC = 7 cm

**Property: **If two tangents are drawn to a circle from one external point, then their tangent segments (lines joining the external point and the points of tangency on circle) are equal.

Using the above property,

CP = CQ = 11 cm (tangent from C)

BQ = BR (tangent from B)

**And,**

AP = AR (tangent from A)

**Now, **

BR = BQ = CQ – CB

= 11 cm – 7 cm

= 4 cm

**Hence, BR = 4 cm**