Given:
a5 = 22
a + 4d = 22 (i)
Acc. to question,
a9 = 6a2 (ii)
a9 = a +8d
a2 = a+d
Putting the value of a9 and a2 in (ii)
a +8d = 6(a +d)
2d = 5a
2d = 5(22 - 4d)
22d = 110
d = 5
Now, putting the value of d in (i)
a = 22 - 4(5) = 2
a1 = a = 2
a2 = a +d = 2 +5 = 7
a3 = a +2d = 2 + 2(5) = 12
Hence, the A.P. is 2, 7, 12, 17,..........