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Find the number of natural numbers between 101 and 999 which are divisible by both 2 and 5.

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We have to find the numbers between 101 and 999 which are divisible by both 2 and 5.

That means the numbers divisible by 10 between 101 and 999.

Let, the required divisible numbers be,

110, 120, 130, …, 990

a = 110, d = 10, last term, l = 990

Number of terms,

= 89

Hence, the number of natural numbers between 101 and 999 which are divisible by both 2 and 5 are 89.

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