Option : (B)
If we consider the above figure as for getting it,their will be many points on the curve.
If the normal to the point B passes through the point(2,1) then point B will be the point having nearest distance from point (2,1).
Let B(x,y)
\(\frac{dy}{dx}\) = \(\frac{2}{y}\)
Slope at the point B is (2/y) and normal’s slope will be m=(–y/2) so by point slope formula.
⇒ (y - y1) = m(x - x1); (x1 = 2,y1 = 1)
⇒ (y - 1) = (-y/2)(x - 2)
⇒2y - 2 = -xy + 2y
⇒ xy = 2; y2 = 4x
⇒ from above to equations y3 = 8
⇒ y = 2 and x =1
So the nearest point is (1,2).