Sarthaks Test
0 votes
11 views
in Arithmetic Progression by (7.9k points)
closed by

If the 5th term of an A.P. is 31 and 25th term is 140 more than the 5th term, find the A.P.

1 Answer

+1 vote
by (8.1k points)
selected by
 
Best answer

a5 = 31

a +4d = 31 (i)

a25 = 140 + a5

a + 24d = 140 + 31

31 - 4d +24d = 171 [ from (i) ]

20d = 140

d = 7

Putting the value of d in (i)

a = 31 – 4(7) = 3

a1 = a = 3

a2 = a +d = 3 +7 = 10

a3 = a +2d = 3 + 2(7) = 17

Hence, the A.P. is 3, 10, 17,…

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...