Sarthaks Test
0 votes
15 views
in Arithmetic Progression by (7.9k points)
closed by

The sum of three terms of an A.P. is 21 and the product of the first and the third terms exceeds these term by 6, find three terms.

1 Answer

+1 vote
by (8.1k points)
selected by
 
Best answer

Let the three terms be a - d, a, a + d

a – d + a + a – d = 21 (given)

3a = 21

a = 7

According to question,

(a – d) (a + d) = a + 6

a 2 – d2 = a + 6

7 2 – d2 = 7 + 6

49 – d2 = 13

d 2 = 36

d = 6

Therefore,

a – d = 7 – 6 = 1

a + d = 7 + 6 = 13

Thus, the three terms are 1, 7 and 13.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...