Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
277 views
in Derivatives by (29.4k points)
closed by

The minimum value of (x2\(\frac{250}{x}\)) is :

A. 75 

B. 50 

C. 25 

D. 55

1 Answer

+1 vote
by (28.3k points)
selected by
 
Best answer

Option : (A)

f(x) = x2\(\frac{250}{x}\)

Differentiating f(x) with respect to x, we get

 f'(x) = 2x - \(\frac{250}{x^2}\)

Differentiating f’(x) with respect to x, we get

 f''(x) = 2 + \(\frac{500}{x^3}\)

For minima at x = c, 

f’(c) = 0 and f’’(c)>0 f’(x) = 0 

⇒ x3 = 125 or x = 5 

f’’(5) = 7>0 

Hence, 

x = 5 is a point of minima for f(x) and f(5) = 75 is the minimum value of (x).

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...