Question

Two cross roads, each of width 10 m, cut at right angles through the centre of a rectangular park of length 700 m and breadth 300 m and parallel to its sides. Find the area of the roads. Also find the area of the park excluding cross roads. Give the answer in hectares.

Answer 1

Here, PQ = 10 m and PS = 300 m, EH = 10 m and EF = 700 m And KL = 10 m and KN = 10 m

Area of roads

= Area of PQRS + Area of EFGH – Area of KLMN

[∵ KLMN is taken twice, which is to be subtracted]

= PS x PQ + EF x EH – KL x KN

= (300 x 10) + (700 x 10) – (10 x 10)

= 3000 + 7000 – 100

= 9,900 m²

Area of road in hectares,

1 m² =1/10000 hectares

9,900 m² =9900/10000

= 0.99 hectares

Now, Area of park excluding cross roads = Area of park – Area of road = (AB x AD) – 9,900

= (700 x 300) – 9,900

= 2,10,000 – 9,900

= 2,00,100 m²

= 200100 hectares = 20.01 hectares