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in Mathematics by (35.7k points)

In the given below fig, rays OA, OB, OC, OP and OE have the common end point O. Show that ∠AOB + ∠BOC + ∠COD + ∠DOE + ∠EOA = 360°.

1 Answer

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Best answer

Given that 

Rays OA, OB, OD and OE have the common end point O. 

A ray of opposite to OA is drawn

By adding (1) and (2) equations we get 

∠AOB + ∠BOC + ∠COF + ∠AOE + ∠DOF + ∠DOE = 360o 

∠AOB + ∠BOC + ∠COD + ∠DOE + ∠EOA =360o 

Hence proved

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