Let I = \(\int\limits_{\pi/3}^{\pi/2}\cfrac{\sqrt{1+cos\text x}}{(1-cos\text x)^{3/2}}d\text x\)
In the denominator, we can write
We also have,
When x = \(\cfrac{\pi}3\), t = cot\(\cfrac{(\frac{\pi}3)}{2}\) = cot \(\cfrac{\pi}6\) = √3
When x = \(\cfrac{\pi}2\), t = cot\(\cfrac{(\frac{\pi}2)}{2}\) = cot \(\cfrac{\pi}4\) = 1
So, the new limits are \(\sqrt3\) and 1.
Substituting this in the original integral,