To find the area of the region bounded by
y = √1 – x2 …(i)
x2 + y2 = 1
x = y …(ii) On solving the equation (i) and (ii),
Or x2 + x2 = 1
Or 2x2 = 1
Or x = \(\pm \frac{1}{\sqrt{2}}\)
Equation (i) represents a circle (0, 0) and meets axes at (±1, 0), (0, ±1).
Equation (ii) represents a line passing through B \(\left(\frac{1}{\sqrt{2}},\frac{1}{\sqrt{2}} \right)\) and \(\left(-\frac{1}{\sqrt{2}},\frac{1}{\sqrt{2}} \right)\) and they are also points of intersection.
These are shown in the graph below:
Required area = Region OABO
= Region OCBO + Region CABC
The area of the region bounded by the curve y = √1 – x2, line y = x is \(\frac{\pi}{8}\) sq. units.