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in Functions by (30.3k points)
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A. void change(int&); 

int main()

{

int x = 0;

change(x);

cout<<"value="<<x;

}

void change(int & y)

{

y = 40;

cout<<"value="<<y;

}

B. void change(int);

int main()

int x = 0;

change(x);

cout<<"value="<<x;

}

void change(int y)

{

y = 40;

cout<<"value="<<y;

}

1. Predict the output of both programs. 

2. Justify your predictions.

1 Answer

+1 vote
by (30.5k points)
selected by
 
Best answer

1. A. Output value = 40 

B. output value = 0

2. In the first case (A) the argument x is passed by reference method. So the changes made in the function reflects in main().

In the second case (B) the argument x is passed by value method. So the changes made in the function will not reflect in main().

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