To find the area enclosed by
y = |x – 1|
Solving both the equation for x < 1
Y = 1 – x and y = x,
We get x = \(\frac{1}{2}\) and y = \(\frac{1}{2}\)
And solving both the equations for x ≥ 1
Y = x – 1 and y = 2 – x,
We get x = \(\frac{3}{2}\) and y = \(\frac{1}{2}\)
These are shown in the graph below :
Required area = Region ABCDA
Required area = Region BDCB + Region ABDA …(1)
The area enclosed by the curves y = |x – 1| and y = – |x – 1| + 1 is \(\frac{1}{2}\) sq. units.