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+1 vote
1.3k views
in Definite Integrals by (29.3k points)
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The area bounded by the parabola x = 4 – y2 and y-axis, in square units, is

A. 3/32

B. 32/3

C. 33/2

D. 16/3

1 Answer

+2 votes
by (28.8k points)
selected by
 
Best answer

Correct answer is B.

Is the blue shaded region.

At points of intersection on y-axis, x = 0

So, equation becomes 0 = 4 – y2 or y = -2, 2

This becomes our bounds, and we integrate w.r.t. the y-axis –

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