Equation of parabola with latus rectum ‘4a’ and axes parallel to x - axes and vertex at (h, k) is given by
(y – k)2 = 4a(x – h)
On differentiating with respect to x we get,
Again differentiating (i) with respect to x we get,
From (i) we have (y - k) = \(\frac{2a}{\frac{dy}{dx}},\) on substituting it in the above equation we get,
Hence, the required differential equation is