To find another zero of the polynomial x2− 4x + 1 , if one of them will be (2 +√3).
Let consider two zeros α, β
(x2− 4x + 1 comparing with general equation ax2+ bx + c, then a = 1,b =−4,c = 1)
α + β = 4
from equation (1) & (2)
α + β = 4
2 + √3 + β = 4
β = 4−(2 + √3)
β = 4 − 2 − √3
β = 2 − √3