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in Definite Integrals by (28.8k points)
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If I10 = \(\int\limits_{0}^{\pi/2} \) x10 sin x dx, then the value of I10 + 90 I8 is

A. 9\(\Big(\cfrac{\pi}2\Big)\)9

B. 10\(\Big(\cfrac{\pi}2\Big)\)9

C. \(\Big(\cfrac{\pi}2\Big)\)9

D.  9\(\Big(\cfrac{\pi}2\Big)\)8

1 Answer

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by (30.0k points)
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Best answer

Correct option is B.10\(\Big(\cfrac{\pi}2\Big)\)9

Use method of integration by parts

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