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in Arithmetic Progression by (31.3k points)
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If the n sum of a certain number of terms starting from first term of an A.P. is 25,22,19,..... is 116. Find the last term.

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Best answer

a = 25, d = -3

n = 8 or n =\(\frac{29}{3}\), which isn’t possible as n must be a natural number.

Therefore, n = 8

\(\frac{n}{2}\)[a + l] = 116

\(\frac{9}{2}\) [25 + l] = 116

25 +l = 29

I = 4

Hence,  the last term is 4

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