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Subtract: 

3a (a + b + c) − 2b (a − b + c) from 4c (− a + b + c)

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3a (a + b + c) − 2b (a − b + c) 

= 3a2 +3ab + 3ac − 2ba + 2b2 − 2bc

= 3a2 + 2b2 + ab + 3ac − 2bc

4c (− a + b + c) = − 4ac + 4bc + 4c2

Subtracting these expressions, we obtain

Therefore, the result is −3a2 −2b2 + 4c2 − ab + 6bc − 7ac.

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