Given,
First term, a1 = 17
Last term, an = 350 = l
And difference, d = 9
We know,
an = a + (n – 1)d
350 = 17 + (n – 1) (9)
350 = 8 + 9n
342 = 9n
n = 38
We know sum of n terms, Sn = \(\frac{n}{2}\)[a + l]
S38 = \(\frac{38}{2}\)[17 + 350]
= 19 x 367 = 6973
Hence, number of terms, n = 38
sum of n terms, Sn = 6973