Correct answer is B. -(P + q)
Sp = \(\frac{p}{2}\){2A + (p–1) D} = q, given
Sq = \(\frac{q}{2}\)(2A + (q–1) D} = p, given
On Subtracting the second equation from 1st we get,
D = –2\(\frac{(P+q)}{Pq}\)
Also On adding the two equations we get,
2A + \(\frac{(P +q -2)D}{2} = \frac{p}{q} + \frac{q} {p}\)
Now
[BY substituting the value of D]
= - (P + q)