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+1 vote
2.1k views
in Arithmetic Progression by (31.3k points)
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If 1/x+2, 1/x+3, 1/x+5 are in A.P. Then x = 

A. 5 

B. 3 

C. 1 

D. 2

1 Answer

+2 votes
by (30.9k points)
selected by
 
Best answer

Here \(\frac{1}{x+2}\)\(\frac{1}{x+3}\),\(\frac{1}{x + 5}\) are in A.P

So \(\frac{1}{x+3}\) - \(\frac{1}{x+2}\)\(\frac{1}{x + 5}\)  -  \(\frac{1}{x+3}\)

–1/(x +3)(x + 2) = –2/ (x + 5)(x + 3) 

1/2 = (x + 2)/(x + 5) 

x + 5= 2x + 4 

x= 1

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