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0 votes
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in Arithmetic Progression by (31.3k points)
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The nth term of an A.P., the sum of whose n terms is Sn, is 

A. Sn + Sn–1 

B. Sn – Sn–1 

C. Sn + Sn + 1 

D. Sn – Sn + 1

1 Answer

+1 vote
by (30.9k points)
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Best answer

The sum of n terms of an A.P is given by Sn 

Sn = \(\frac{n}{2}\)(2a + (n–1) d)

 If the sum of n terms is given that is Sn is given then the nth term is given by the formula 

Tn = Sn– Sn–1 Where Sn–1 is sum of the (n–1)th term of the A.P.

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