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If a vector makes angles α, β, γ with OX, OY and OZ respectively, then write the value of sin2α + sin2β + sin2γ.

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The sum of squares of direction cosines of a vector is 1.

Let the angles made by vector be α, β, γ.

Then, we get cos2α+cos2β+cos2γ=1

using cos2θ=1 - sin2θ, we get

(1 - sin2α) +(1 - sin2β) + (1 - sin2γ) = 1

Or, sin2α + sin2β + sin2γ = 2

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