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Find the position vector of the mid-point of the line segment AB, where A is the point (3, 4, –2) and B is the point (1, 2, 4).

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If the co-ordinates of a point A≡ (x1, y1, z1), then the position vector of A(\(\vec a\)) is

Given that A ≡ (3, 4, 2) and B ≡ (1, 2, 4), we get position vector of A( \(\vec a\)) and B( \(\vec b\)). Let the midpoint be C(\(\vec c\))

The position vector of midpoint of two vectors is defined by  \(\cfrac{\vec a+\vec b}2\)

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